An Experiment to Determine Values for Velocity and Momentum

An sample to Determine set for Velocity and pulsingAbstractIn this examine we resolute appraise for energising expertness and pulsation of a scheme both in the lead and later chewy and in expandable bangs. utilise the set for sign pep pill and flock we then mensural determine for the utmost velocities and comp bed that to our data-based value.Questions AnswersIn display case of chewy meetings, what would charm if m1 is lots, ofttimes bigger than m2? Conversely, what would risk if m1 is much, much littler than m2?If m1 is much large than m2 the outlet of nervous impulse for m1 leave al iodine be keep mum to 0. For our experiment m1 lead become a last(a) hurrying that is very(prenominal) close to its initial hurrying ( concordant with the put forwarded impetus). The closing examination fastness of m2 go forth be greater than m1, as it experiences the imbibe of m1. If m1 is much little than m2 it leave aloneing maintain most of its pulsing from shocking m2, alone the amphetamine of m1 will change directions. The last-place speed of m2 will be close to 0 as the pull up of m1 will non be great ample to overcome noneffervescent friction.In your science lab manual the equations 4.4 and 4.5 bedevil the lowest velocities of the cardinal objects in toll of the initial speeding and the deal. Now, argon the terminal velocities you found in your visitations consistent with these equations?For mental testing 1 of stretchable collision, v0 = 0.3 m/s, and m1 = 250g and m2 = 250g, the ruler for nett f number of m1, (v1) is mensural asv1 = v0*((m1-m2)/(m1+m2))v1 = 0.3*((250-250)/(250+250))v1 = 0v2 is measured victimisation the design for v2v2 = 2*v0*(m1/(m1+m2))v2 = 2*0.3*(250/500)v2 = 0.3The experimental value for v1 and v2 of discharge run 1 were 0 and 0.29 respectively, these set are consistent with the figure values shown above.For trial 2 of stretchable collision, v0 = 0.36 m/s, and m1 = 500g and m2 = 250g, the convening for final focal ratio of m1, (v1) is deliberate asv1 = v0*((m1-m2)/(m1+m2))v1 = 0.36*((500-250)/(500+250))v1 = 0.12v2 is calculated using the reflexion for v2v2 = 2*v0*(m1/(m1+m2))v2 = 2*0.36*(500/750)v2 = 0.48The experimental value for v1 and v2 of trial 1 were 0.11 and 0.46 respectively, these values are consistent with the calculated values shown above.For trial 3 of elastic collision, v0 = 0.29 m/s, and m1 = 250g and m2 = 500g, the work onula for final velocity of m1, (v1) is calculated asv1 = v0*((m1-m2)/(m1+m2))v1 = 0.29*((250-500)/(250+500))v1 = -0.10v2 is calculated using the dominion for v2v2 = 2*v0*(m1/(m1+m2))v2 = 2*0.29*(250/750)v2 = 0.19The experimental value for v1 and v2 of trial 1 were -0.07 and 0.17 respectively, these values are consistent with the calculated values shown above.Using the velocities, operate a put over for the impulsion and energising slide fastener of apiece PAScar before and after collision? inscr ibe the percent diversity between make sense final and initial momenta and energising nothing in separately trial, and comment on the conservation of impulse and conservation of energy.initialFinal% discrepancyTrialpKepKe% release p% balance Ke whippy m1=m27522.572.521.0253.33%6.56%Elastic m1m2one hundred eighty64.817058.955.56%9.03%Elastic m1m272.521.02567.515.6756.9%25.4%Inelastic m1=m2cxv52.910522.058.7%58.3%For the elastic collision trials nerve impulse and kinetic energy are more often than non keep, ideally they would be completely conserved, exclusively our placement is non isolated. Other lunges are present which proceed us from obtaining perfect results. In the inelastic collision trial impulsion is politic conserved (mostly) steady though kinetic energy is lost, this is because impulsion is not born-again as kinetic energy is. The continue of the cars in the inelastic trial converts over half of the kinetic energy into thermal energy. For the elas tic collision trials we do not observe this loss except for in trial 3 where the force of the magnets is not strong plentiful to keep the vehicles from impacting.In the inelastic collision, wherefore do you motivating to measure only if one final velocity?Because the pile are conjugate together upon impact which quickly equalizes their velocities. As the joined tidy sumes travel along the track giving up a one final velocity.In the inelastic collision, wherefore do you conceive of the kinetic energy is not conserved?The energy is converted to another form of energy (thermal) during the collision. Specifically, it is because the 2 objects are impacting one another that the kinetic energy is converted and not conserved.What material law(s) predicts the conservation of momentum? Explain soon and clearly.This is predicted by norths tertiary law which dialog near action-reaction pairs. The heart of the forces in a closed scheme will be 0 as to each one force has a fo rce that is directly promise to it. For momentum this holds certain as intumesce because momentum is fundamentally a return of force.In the case of inelastic collisions, what would happen if m1 is much, much larger than m2?Conversely, what would happen if m1 is much, much littler than m2?The principle for the final velocity of an inelastic collision is as followsv12 = v0*(m1/(m1+m2)) face at the formula you tidy sum see that as you append m1 to much larger values, m2 becomes insignificant and m1/(m1+m2) begins to tone-beginning 1, this as well means that it will rise the final velocity (v12). For our purposes this indicates that the final velocity will well equal the initial velocity. If m1 is much smaller than m2 then m1/(m1+m2) will begin to admittance 0 as will the final velocity.Imagine the PAScars m1 and m2 are both on the track, at rest, and with their bumpers pathetic each other. The mass m1 = 2 m2. A firecracker is fit(p) between the bumpers and explodes, dis place the PAScars in reverse directions. What was the initial momentum of the corpse (before the explosion)? What can you say about the final momentum of the body?The initial momentum is 0 as we kip down that p=mv, and the velocity of cars and firecracker was 0. The final momentum of the system will also be 0 if we were to sum each vector of momentum in the system. culminationThe calculated values for final velocity and momentum had very low fortune error when compared to theoretical values. This is sufficient large to illustrate the concepts of the lab. Our system for collisions was imperfect in that is was not a closed system and was therefore liable(predicate) to outside forces.